(* Title: HOL/Library/Primes.thy
ID: $Id: Primes.thy,v 1.17 2005/07/08 09:39:08 nipkow Exp $
Author: Christophe Tabacznyj and Lawrence C Paulson
Copyright 1996 University of Cambridge
*)
header {* Primality on nat *}
theory Primes
imports Main
begin
constdefs
coprime :: "nat => nat => bool"
"coprime m n == gcd (m, n) = 1"
prime :: "nat => bool"
"prime p == 1 < p ∧ (∀m. m dvd p --> m = 1 ∨ m = p)"
lemma two_is_prime: "prime 2"
apply (auto simp add: prime_def)
apply (case_tac m)
apply (auto dest!: dvd_imp_le)
done
lemma prime_imp_relprime: "prime p ==> ¬ p dvd n ==> gcd (p, n) = 1"
apply (auto simp add: prime_def)
apply (drule_tac x = "gcd (p, n)" in spec)
apply auto
apply (insert gcd_dvd2 [of p n])
apply simp
done
text {*
This theorem leads immediately to a proof of the uniqueness of
factorization. If @{term p} divides a product of primes then it is
one of those primes.
*}
lemma prime_dvd_mult: "prime p ==> p dvd m * n ==> p dvd m ∨ p dvd n"
by (blast intro: relprime_dvd_mult prime_imp_relprime)
lemma prime_dvd_square: "prime p ==> p dvd m^Suc (Suc 0) ==> p dvd m"
by (auto dest: prime_dvd_mult)
lemma prime_dvd_power_two: "prime p ==> p dvd m² ==> p dvd m"
by (rule prime_dvd_square) (simp_all add: power2_eq_square)
end
lemma two_is_prime:
prime 2
lemma prime_imp_relprime:
[| prime p; ¬ p dvd n |] ==> gcd (p, n) = 1
lemma prime_dvd_mult:
[| prime p; p dvd m * n |] ==> p dvd m ∨ p dvd n
lemma prime_dvd_square:
[| prime p; p dvd m ^ Suc (Suc 0) |] ==> p dvd m
lemma prime_dvd_power_two:
[| prime p; p dvd m² |] ==> p dvd m