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Lesson: Exceptions
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Answers to Questions and Exercises

### Questions

> 1. Question: Is the following code legal?

>    >     try {

>    >     } finally {

>    >     }

>    Answer: Yes, it's legal — and very useful A `try` statement does not have to have a `catch` block if it has a `finally` block. If the code in the `try` statement has multiple exit points and no associated `catch` clauses, the code in the `finally` block is executed no matter how the `try` block is exited. Thus it makes sense to provide a `finally` block whenever there is code that must always be executed. This include resource recovery code, such as the code to close I/O streams.

> 2. Question: What exception types can be caught by the following handler?

>    >     catch (Exception e) {

>    >     }

>    What is wrong with using this type of exception handler?

>    Answer: This handler catches exceptions of type `Exception`; therefore, it catches any exception. This can be a poor implementation because you are losing valuable information about the type of exception being thrown and making your code less efficient. As a result, your program may be forced to determine the type of exception before it can decide on the best recovery strategy.

> 3. Question: Is there anything wrong with this exception handler as written? Will this code compile?

>    >     try {

>    >     } catch (Exception e) {

>    >     } catch (ArithmeticException a) {

>    >     }

>    Answer: This first handler catches exceptions of type `Exception`; therefore, it catches any exception, including `ArithmeticException`. The second handler could never be reached. This code will not compile.

> 4. Question: Match each situation in the first list with an item in the second list.
>    1. `int[] A;
>       A[0] = 0;`
>    2. The JVM starts running your program, but the JVM can't find the Java platform classes. (The Java platform classes reside in `classes.zip` or `rt.jar`.)
>    3. A program is reading a stream and reaches the `end of stream` marker.
>    4. Before closing the stream and after reaching the `end of stream` marker, a program tries to read the stream again.

>    1. __error
>    2. __checked exception
>    3. __compile error
>    4. __no exception

>    Answer:

>    1. 3 (compile error). The array is not initialized and will not compile.
>    2. 1 (error).
>    3. 4 (no exception). When you read a stream, you expect there to be an end of stream marker. You should use exceptions to catch unexpected behavior in your program.
>    4. 2 (checked exception).

### Exercises

> 1. Exercise: Add a `readList` method to ``ListOfNumbers.java``. This method should read in `int` values from a file, print each value, and append them to the end of the vector. You should catch all appropriate errors. You will also need a text file containing numbers to read in.

>    Answer: See ```ListOfNumbers2.java``.`

> 2. Exercise: Modify the following `cat` method so that it will compile:

>    >     public static void cat(File file) {
>    >         RandomAccessFile input = null;
>    >         String line = null;

>    >         try {
>    >             input = new RandomAccessFile(file, "r");
>    >             while ((line = input.readLine()) != null) {
>    >                 System.out.println(line);
>    >             }
>    >             return;
>    >         } finally {
>    >             if (input != null) {
>    >                 input.close();
>    >             }
>    >         }
>    >     }

>    Answer: The code to catch exceptions is shown in red:

>    >     public static void cat(File file) {
>    >         RandomAccessFile input = null;
>    >         String line = null;

>    >         try {
>    >             input = new RandomAccessFile(file, "r");
>    >             while ((line = input.readLine()) != null) {
>    >                 System.out.println(line);
>    >             }
>    >             return;
>    >         } catch(FileNotFoundException fnf) {
>    >             System.err.format("File: %s not found%n", file);
>    >         } catch(IOException e) {
>    >             System.err.println(e.toString());
>    >         } finally {
>    >             if (input != null) {
>    >                 try {
>    >                     input.close();
>    >                 } catch(IOException io) {
>    >                 }
>    >             }
>    >         }
>    >     }

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